Question

simplifique:

a_ √50 - √98
b_ √12 - 6√3
c_ 8√5 - √20
d_ √20 -√45
e_ 2√50 + 6√2
f_√98 + 5√18
g_ 3√98 - 2√50
h_3√8 - 7√50
i_√75 - 2 √12 √27
j_ √12 - 9√3 + √75
k_ √98 - √18 - 5 √32
L_ 5√180 + √245 = 17√5

Answer 1

e_ 2√50 + 6√2 = 2.$\sqrt{2.25}$ + 6$\sqrt{2}$ = 2.5$\sqrt{2}$ + 6$\sqrt{2}$ = 16$\sqrt{2}$
f_√98 + 5√18 = $\sqrt{2.49}$ + 5.3$\sqrt{2.9}$ = 7$\sqrt{2}$ + 15$\sqrt{2}$ = 22$\sqrt{2}$
g_ 3√98 - 2√50 = 3$\sqrt{2.49}$ - 2$\sqrt{2.25}$ = 7.3$\sqrt{2}$ - 2.5$\sqrt{2}$ = 21$\sqrt{2}$ - 10$\sqrt{2}$ = 11$\sqrt{2}$
h_3√8 - 7√50 = 3$\sqrt{2.4}$ - 7.$\sqrt{2.25}$ = 2.3$\sqrt{2}$ - 5.7$\sqrt{2}$ = 6$\sqrt{2}$ - 35$\sqrt{2}$ = - 29$\sqrt{2}$
i_√75 - 2 √12 √27 falta um sinal
j_ √12 - 9√3 + √75 = $\sqrt{4.3}$ - 9$\sqrt{3}$ - $\sqrt{3.25}$ = 2$\sqrt{3}$ - 9$\sqrt{3}$ - 5$\sqrt{3}$ = -12$\sqrt{3}$
k_ √98 - √18 - 5 √32 = $\sqrt{2.49}$ - $\sqrt{2.9}$ - 5$\sqrt{2.16}$ = 7$\sqrt{2}$ - 3$\sqrt{2}$ - 5.4$\sqrt{2}$ = 7$\sqrt{2}$ - 3$\sqrt{2}$ - 20$\sqrt{2}$ = - 16$\sqrt{2}$
L_ 5√180 + √245 = 17√5 No lugar do sinal = deve ser outro sinal