Question

simplifique 8m²-8n²/2n-2m

Answer 1

$\frac{8m^2-8n^2}{2m-2n} = \frac{8(m^2-n^2)}{4(m-n)}$

$4\frac{(m^2-n^2)}{(m-n)} =4 \frac{(m+n)(m-n)}{(m-n)}$

$4\frac{(m+n)(m-n)}{(m-n)} = 4\frac{m+n}{1} =4m+4n$