Question

simplifique 7!/4!x3! fatorial

Answer 1

$\displaystyle A=\frac{7!}{4!\times 3!}\\ \\ A=\frac{7\times6\times5\times4!}{4!\times 3!}\\ \\ A=\frac{7\times6\times5}{3!}\\ \\ A=\frac{7\times6\times5}{6}\\ \\ A=7\times 5\\ \\ \boxed{A=35}$