Question

Simplificar a expressão
(y+1)!+y! ​/ (y+2)! =​

Answer 1

Resposta:
(y+1)!+y! ​/ (y+2)!
(y+1).y!+y! ​/ (y+2)!.(y+1).y!
y!.[y+1 + 1] / (y+2)!.(y+1).y!
[Y+2] / (y+2)!.(y+1)
1 / y+1

Explicação passo a passo:

Answer 2

$\sf\dfrac{(y+1)!+y!}{(y+2)!}$

$\sf\dfrac{(y+1)\cdot y!+y!}{(y+2)\cdot(y+1)!}$

$\sf\dfrac{(y+1+1)\cdot y!}{(y+2)\cdot(y+1)\cdot y!}$

$\sf\dfrac{\cancel{(y+2)}\cdot1}{\cancel{(y+2)}\cdot(y+1)}$

$\boxed{\boxed{\sf\dfrac{(y+1)!+y!}{(y+2)!}=\dfrac{1}{y+1}}}$