Question

simplificando a espressao (x^(2x-1)*y^(x+1))/(x^(1+2x)*y^x) obtemos:

A) x^2*y
b) x^2/y
c) y/x^2
D) y^2/x
e) x/y^2

Answer 1

$\frac{x^{(2x-1)}.y^{x+1}}{x^{(1+2x)}.y^x} = \\ \\ x^{2x-1-(1+2x)}.y^{x+1-x}= \\ \\ x^{2x-1-1-2x}.y^1= \\ \\ x^{-2}.y= \frac{y}{x^2} \\ \\ Letra~~C$