Question

Sendo z=2 (cos pi/4 + i sen pi/4), calcule z3.​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{z = 2\:.\:\left(cos\:\dfrac{\pi }{4} + i\:.\:sen\:\dfrac{\pi }{4}\right)}$

$\mathsf{z^3 = 2\:.\:\left(cos\:\dfrac{\pi }{4} + i\:.\:sen\:\dfrac{\pi }{4}\right)^3}$

$\mathsf{z^3 = 2^3\:.\:\left(cos\:3\:.\:\dfrac{\pi }{4} + i\:.\:sen\:3\:.\:\dfrac{\pi }{4}\right)}$

$\boxed{\boxed{\mathsf{z^3 = 8\:.\:\left(cos\:3\:.\:\dfrac{\pi }{4} + i\:.\:sen\:3\:.\:\dfrac{\pi }{4}\right)}}}$