Question

sendo y=x^2-7x+6 determine os valores de x para a)y=0 b)y=-6

Answer 1

${x}^{2} - 7x + 6 = 0 \\ { (- 7)}^{2} - 4.1.6 = 49 - 24 = 25 \\ x1 = \frac{7 + \sqrt{25} }{2} = 6 \\ x2 = \frac{7 - \sqrt{25} }{2} = 1$

${x}^{2} - 7x + 6 = - 6 > {x}^{2} - 7x + 12 \\ {( - 7)}^{2} - 4.1.12 = 49 - 48 = 1 \\x1 = \frac{7 + \sqrt{1} }{2} = 4 \\ x2 = \frac{7 - \sqrt{1} }{2} = 3$