Question

Sendo x²+1/x²=5, calcule o valor de: (x-1)²
(X)

Answer 1

$\frac{x^2+1}{x^2} =5\\ \\ \frac{(x^2-1)^2(x^2+1)}{x^2} =5(x^2-1)^2\\ \\ (x^2-1)^2(x^2+1)=5(x^2-1)^2x^2\\ \\(x^2-1)^2 = \frac{5(x^2-1)^2x^2}{x^2+1} \\ \\ x.(x^2-1)^2 = \frac{5(x^2-1)^2x^3}{x^2+1}$

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