Question

SENDO X=7º:7¹+7:7² e y=4¹+(4³.4):4² , calcule o valor de 7x+4y

Answer 1

 X=7º:7¹+7:7² e y=4¹+(4³.4):4² , calcule o valor de 7x+4y

 X=7º:7¹+7:7²  = 7^-1 + 7^-1 = 2.7^-1

y=4¹+(4³.4):4² ==> 4 + 4^4:4^2 ==> 4 + 4^2 ==> 4+16 = 20 


7x+4y ==>  7(2.1) + 20 ==> 2 + 20 ==> 22
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