Question

Sendo x=(2²)³,y=2⅔ e z=2⅔,o valor de xyz é:

Answer 1

Bom dia, vamos lá.

$x = (2^2)^3 = 2^{(2.3)} = 2^6 \\\\ y = 2^{2^3} = 2^{2.2.2} = 2^8 \\\\ z = 2^{3^2} = 2^{3.3} = 2^9 \\\\\\ xyz = 2^6~.~2^8~.~2^9 \\ xyz = 2^{6+8+9}\\ \boxed{xyz = 2^{23}}$