Question

sendo x=(2²)³ y=(2)⁴ e z =(2-²) determine o valor de x.y.z​

Answer 1

Resposta:

$\left(2^2\right)^3=64$

$\left(2^1\right)^4=16$

$2^{-2}=\frac{1}{4}$

$x.y.z=64\cdot \:16\cdot \frac{1}{4}=256$

Answer 2

X . Y . Z =
= (2²)³ . (2)⁴ . (2-²)
= (2 ^ 6) . 2⁴ . 2-²
= 2 ^ 6 + 4 + (-2)
= 2 ^ 8
= 256