Question

sendo
$a = \frac{x {}^{ - 4 } \times ( {x}^{ - 2} \times {y}^{6} {)}^{ - 3} }{ {x}^{6} \times ( {x}^{ - 3} \times {y}^{ - 8} {)}^{4} }$
considere
X=(2) e Y=(-1)​

Answer 1

Resposta:

$a = \frac{x {}^{ - 4 } \times ( {x}^{ - 2} \times {y}^{6} {)}^{ - 3} }{ {x}^{6} \times ( {x}^{ - 3} \times {y}^{ - 8} {)}^{4} } \\ a = \frac{ {2}^{ - 4} \times{ ( {2}^{2} \times {( - 1)}^{6})}^{ - 3} }{{2}^{6} \times {( {2}^{ - 3} \times { ( - 1)}^{ - 8} ) }^{4} } \\ a = \frac{ {2}^{ - 6} }{ {2}^{ - 2} } = \frac{1}{ {2}^{4} } = \frac{1}{16}$

Espero Ter Ajudado !!