Question

sendo p(x)=3x^4+2x^3+x^2-x+1,calcule:

a)P(2)

b)P(-1)

c)P(0)+P(1)

Answer 1

p(x)= 3x⁴+2x³+x²-x+1

a) p(2)= 3.2⁴+2.2³+2²-2+1

p(2)= 3.16+2.8+4-2+1

p(2)= 48+16+4-2+1

p(2)=64+4-2+1

p(2)=68-2+1

p(2)= 66+1

p(2)=67




b) p(x)=3x⁴+2x³+x²-x+1

p(-1)= 3.(-1)⁴+2.(-1)³+(-1)²-1+1

p(-1)= 3.1+2.(-1) +1-1+1

p(-1)= 3-2+1-1+1

p(-1)= 1+1-1+1

p(-1)= 2-1+1

p(-1)=1+1

p(-1)= 2


c) p(0)=3.0⁴+2.0³+0²-0+1

p(0)= +1

p(1)= 3.1⁴+2.1³+1²-1+1

p(1)= 3 +2 +1 -1 +1

p(1)= 5+1-1+1

p(1)= 6-1+1

p(1)=6


p(0)+p(1)= 1+6=7