Question

Sendo logx 2 = a, logx 3 = b Calcule logx de raiz cúbica de 12

Answer 1

logx 2 = a
logx 3 = b


logx ³√12 =
logx ³√(2²  . 3) =
logx ³√2² + logx ³√3 =
logx 2^(2/3) + logx 3^(1/3) =
2/3logx 2 + 1/3logx 3 =
(2/3) * a + (1/3) * b =
2a/3 + b/3 = 
(2a + b) /3

Answer 2

Resposta:

1/3(2a+b).

Explicação passo-a-passo:

97d69de5b40dc89eee65a43fc51cc2bf.pdf