Question

Sendo log2=0,3010 e log3=0,4771, calcule :a) log 50

Answer 1

$log(50) = log(5.10) = log(5) + log(10) \\ log( \frac{10}{2} ) + 1 \\ log(10) - log(2) + 1 \\ 1 - 0.3010 + 1 = 1.699$