Question

Sendo log2=0,3010 e log3=0,4771, calcule :
a) log 16
b) log 12
c) log 27

Answer 1

a) log 16 = log 2^4 = 4 log 2 = 4 . 0,3010 = 1.204

b) log 12 = log 3.4 = log 3 + log 2² = log 3 + 2log 2 = 0,4771 + 2 . 0,3010 = 1,078

c) log 27 = log 3³ = 3 log 3 = 3 . 0,4771 = 1,43

Espero ter ajudado