Question

Sendo
log10 de 2 = 0,301;
log10 de 3 = 0,477;
log10 de 5 = 0,699, calcule:
a)log2 de 50
b)log2 de 6
c)log9 de 2
d)log5 de 3

Answer 1

Ola Amigo Espero Ajudar.

a) Log250=Log(50) ÷ Log(2) Log(50)= 1.69897000434 Log(2)=0.301029995664 Log250=1.69897000434 ÷ 0.301029995664

Resposta : 5.64385618977

b) Log26=Log(6) ÷ Log(2) Log(6)= 0.778151250384 Log(2)=0.301029995664 Log26=0.778151250384 ÷ 0.301029995664

Resposta : 2.58496250072

c) Log92=Log(2) ÷ Log(9) Log(2)= 0.301029995664 Log(9)=0.954242509439 Log92=0.301029995664 ÷ 0.954242509439

Resposta: 0.315464876786

d) Log53=Log(3) ÷ Log(5) Log(3)= 0.47712125472 Log(5)=0.698970004336 Log53=0.47712125472 ÷ 0.698970004336

Resposta: 0.682606194486