Question

Sendo log x 2=a,log x 3=b .Calcle log x raiz de 12 ?

Answer 1

logᵪ  

(1/2) * logᵪ 12 

(1/2) * logᵪ 2² * 3 

(1/2)* [2 * logᵪ2 + logᵪ 3] 

(1/2)* [2 * a+ b] 

=(2a+b)/2

Sabe-se que o Logx 2=a e Log x 3=b  substitui