Question

Sendo log 2= x e log 3 =y , calcular a) log 42 b) log 27 raiz 8

Answer 1

Resposta:

a)É log de 42 mesmo ???

b) 3y+3/2x

Explicação passo-a-passo:

log42 fatorando 42 = 2*3*7

log 2 * 3 * 7

log2 + log3 + log7

x + y + log7

b)

$log(27 \sqrt{8} ) \\ log(3 \times 3 \times 3 \ \times {8}^{ \frac{1}{2} } ) \\ log( {3}^{3} \times {8}^{ \frac{1}{2} } ) \\ 3 log(3) + \frac{1}{2} log(8) \\ 3y + \frac{1}{2} log( {2}^{3} ) \\ 3y + \frac{3}{2} x \: \: ou \: \frac{6y + 3x}{2}$