Question

sendo log 2 = 0 30, log 3 = 0 47 e log 5 = 0 69 calcule log 60.

Answer 1

$\log(60)=\\\\\log(2^2\cdot3\cdot5)=\\\\\log(2^2)+\log(3)+\log(5)=2\log(2)+\log(3)+\log(5)=\\\\2\cdot0.3+0.47+0.69=0.6+0.47+0.69=1.76$