Question

sendo f(x)=x2-2x e g(x)=x-1, encontre f(g(-3))​

Answer 1

$f(x) = {x}^{2} - 2x \\ g(x) = x - 1 \\ f(g(x)) = {(x - 1)}^{2} - 2(x - 1) \\ {x}^{2} - 2x + 1 - 2x + 2 \\ = {x}^{2} - 4x + 3 \\ f(g(x)) = {x}^{2} - 4x + 3 \\ f(g( - 3)) = {( - 3)}^{2} - 4 \times ( - 3) + 3 = \\ 9 + 12 + 3 = 24$