Question

sendo dados:log2=0,301,log3=0,4771 e log5=0,699,calcule o valor de log6-log0,5

Answer 1

$log6 - log 0,5 = log (3.2) - log (\frac{5}{10}) = \\ \\ log3+log2-(log5-log10)=log3+log2-log5+log10 = \\ \\ 0,4771 + 0,3010-06990+1=1,0791$

Answer 2

 log6-log0,5 ==> log(2.3) - log(5/10)

log2 + log3 -(log5 - log10)
log2 + log3 - log5+ 1
0,301 + 0,4771 - 0,699 + 1

  1,0791