Question

Sendo a função f(x) = x³-3 determine x para:
a) f(x) = 0
b) f(x) = -3
c) f(x) = -2
d) f(x) = -4

Answer 1

✔OLÁ!!!

$f(x) = {x}^{3} - 3$

$a)0 = {x}^{3} - 3 \\ - {x}^{3} = - 3( - 1) \\ {x}^{3} = 3 \\ x = \sqrt[3]{3}$

$b) - 3 = {x}^{3} - 3 \\ - {x}^{3} = - 3 + 3 \\ - x {}^{3} = 0( - 1) \\ x {}^{3} = 0 \\ x = 0$

$c) - 2 = {x}^{3} - 3 \\ - {x}^{3} = - 3 + 2 \\ - {x}^{3} = - 1( - 1) \\ {x}^{3} = 1 \\ x = 1$

$d) - 4 = {x}^{3} - 3 \\ - {x}^{3} = - 3 + 4 \\ - {x}^{3} = 1( - 1) \\ {x}^{3} = - 1 \\ x = - 1$