Question

Sendo(4y+4y)²=48, calcule o valor de 64y³+64y³.

Answer 1

Resposta:

$768 \sqrt{6}$

Explicação passo-a-passo:

(4y+4y)²=48

8y²=48

y²=48/8

y²=6

$y = \sqrt{6}$

$64 \times { \sqrt{6} }^{3} + 64 \times { \sqrt{6} }^{3} = 128 { \sqrt{6} }^{3} = 128 \sqrt{ {6}^{2} } . \sqrt{6} = 128.6 \sqrt{6} = 768 \sqrt{6}$