Question

Sejam x, y, b reais positivos, b diferente de 1. Sabendo que logb x = -2 e logb y = 3, calcule o valor dos seus seguintes logaritmos

Answer 1

a) $log_{b} (x*y) = log_{b} x+ log_{b}y = -2+3=1$

b)$log_{b} ( \frac{x}{y} )= log_{b}x - log_{b} y = -2-3 =-5$

c)$log_{} ( x^{3} * y^{2} )=3 log_{b} x+2 log_{b} y=3*(-2)+2*3 =0$

d)$log_{b} ( \frac{ y^{2} }{ \sqrt{x} } )=2 log_{b} y- \frac{1}{2} log_{b} x=2*3- \frac{1}{2}*(-2) = 7$

e)$log_{b} ( \frac{x* \sqrt{y} }{b} )= log_{b} x- log_{b} b+ \frac{1}{2} log_{b} y=-2-1+ \frac{1}{2} *3=- \frac{3}{2}$

Answer 2

Resposta:

E a F? Algm sabe?