Question

Sejam os pontos A(2,5), B(10,-1) e C(9,-2), calcule o perímetro do triângulo ABC

Answer 1

A(2,5) ; B(10 , -1) ; C(9 , -2)

AB = (10-2 , -1-5) = (8 , -6)
BC = (9-10 , -2+1) = (-1 , -1)
CA = (2-9 , 5+2) = (-7 , 7)

|AB| = ((8^2)+(-6^2))^(1/2) = 10
|BC| = ((-1^2)+(-1^2))^(0.5) = 2^(0.5) = 1.4142
|CA| = ((-7^2)+(7^2))^(0.5) = 9.89

Pt = 10 + 1.4142 + 9.89
Pt = 21.3