Question

seja tg(x) = 3/4 e que π <x< 3π/2 então sen x vale ? ​

Answer 1

tgx= 3/4

cotgx = 4/3

cotg²x = 16/9

cos²x/sen²x = 16/9

cos²x+sen²x/sen²x = 16+9/9

1/sen²x = 25/9

sen²x = 9/25

Senx = -√9/25 = -3/5 ✓