Question

seja
$\sqrt{ {13}^{2} } - {12}^{2} = \sqrt[n]{125}$
O valor de (n) e?
(a) 1
(b)2
(c)3
(d)4

Answer 1

$\sqrt{13^2-12^2} = \sqrt[n]{125} \\ \\ \sqrt{169-144} = \sqrt[n]{125} \\ \\ \sqrt{25} = \sqrt[n]{125} \\ \\ 5= \sqrt[n]{5^3} \\ \\ 5^1=5^{ \frac{3}{n}} \\ \\ 1= \frac{3}{n} \\ \\ n=3 \\ \\ letra~~C$