Question

seja f uma funçao com dominio real, dada pela lei f(x)=x2-2x+3 a) f(0) b) f(1/2) c) f (-1) calcule

Answer 1

f(x) = x² - 2x + 3

a) f(0)
f(0) = 0² - 2.0 + 3
f(0) = 0 - 0 + 3
f(0) = 3

b) f(1/2)
f(1/2) = (1/2)² - 2.(1/2) + 3
f(1/2) = 1/4 - 2/2 + 3
f(1/2) = 1/4 - 1 + 3
f(1/2) = 1/4 + 2
f(1/2) = (1 + 2.4)/4
f(1/2) = (1 + 8)/4
f(1/2) = 9/4

c) f(-1) 
f(-1) = (-1)² - 2.(-1) + 3
f(-1) = 1 +2 + 3
f(-1) = 6

bons estudos!!