Question

Se x1 e x2 são as raízes de x2 + 50x - 150 = 0, então (1/x1)+(1/x2) vale:

Answer 1

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$\frac{1}{x_1} + \frac{1}{x_2} = \frac{x_2+x_1}{x_1.x+2} \\ \\ x_1+x_2=- \frac{b}{a} =-50 \\ \\ x_1.x_2= \frac{c}{a} =-150 \\ \\ logo \\ \\ \frac{1}{x_1}+ \frac{1}{x_2}= } \frac{-50}{-150} = \frac{1}{3}$