Question

Se x=2y , y=3z e xyz =3888.Qual é o valor de x+y+z?

Answer 1

x =  2 y e  y = 3z ⇒ x = 2 * (3z) = 6z ⇒ x = 6z

x * y * z = 3888

6z * 3z * z = 3888

18z³ = 3888

z³ = 216 ⇔ z = ∛216 ⇔ z = 6

Portanto: 

x = 6z ⇔ x = 36

y = 3z ⇔ x = 18

z = 6 

x + y + z = 36 + 18 + 6 = 60

x + y + z = 60

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12/02/2016
Sepauto - SSRC
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Answer 2

x= 2.3z=6z∴ 6z. 3z. z=3888∴ 18z^3=3888∴z^3=3888/18∴ z^3=216∴ z= ∛216∴ z= ∛6^3=6∴ y=3.6=18 x= 2.18=36 36+18+6= 60