Question

Se sec×=9/4,calcule sen×,cos× e tg×

Answer 1

cos x = 1 / (sec x) = 1 / (9/4) = 4/9

sen x = √(1 - cos² x) = √(1 - (4/9)² ) = √(1 - 16/81) = √(65/81) = (√65)/9

tg x = (sen x) / (cos x) = ((√65)/9) / (4/9) = (√65) / 4