Question

se o log 2=0,301 calcule a expressao de log 20+log 40+log 800​

Answer 1

Resposta: 5.8

Explicação passo a passo:

Answer 2

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\boxed{\sf log\:2 = 0,301}$

$\sf log\:20 + log\:40 + log\:800$

$\sf log\:(2\:.\:10) + log\:(4\:.\:10) + log\:(8\:.\:100)$

$\sf log\:(2\:.\:10) + log\:(2^2\:.\:10) + log\:(2^3\:.\:10^2)$

$\sf (log\:2 + log\:10) + (2\:.\:log\:2 + log\:10) + (3\:.\:log\:2 + 2\:.\;log\:10)$

$\sf (0,301 + 1) + (2\:.\:0,301 + 1) + (3\:.\:0,301 + 2\:.\:1)$

$\sf (0,301 + 1) + (0,602 + 1) + (0,903 + 2)$

$\sf (1,301) + (1,602) + (2,903)$

$\boxed{\boxed{\sf log\:20 + log\:40 + log\:800 = 5,806}}$