Question

Se n! =1/48 (n+2)!+(n+1)!

Answer 1

n!/[(n+2)!+(n+1)!]=1/48 

n!/[(n+2)(n+1)n!+(n+1)n!]=1/48 

1/[(n+2)(n+1)+(n+1)]=1/48 

48=n²+3n+2+n+1 

n²+4n+3=48 

n²+4n-45=0 

n'=[-4+(16+180)¹/²]/2=5 

n"=[-4-(16+180)¹/²]/2<0, ñ existe fatorial negativo 

Resposta { 5 }