Question

Se log 204 = A e log 206 =B, então o valor de log 205 é?

Answer 1

Resposta:

B=log 206

A=log 204

C =log 205

206= 10^B

204=10^A

205 = 10^C

206-205 =10^B -10^C

205-204=10^C-10^A

10^B -10^C = 10^C-10^A

2*10^(C) =10^(B)-10^(A)

10^(C) = (1/2)*10^(B) - (1/2)*10^(A)

log 10^(C) = log [(1/2)*10^(B) - (1/2)*10^(A)]

C = log [(1/2)*10^(B) - (1/2)*10^(A)]

log 205  =  log [(1/2)*10^(log 206) - (1/2)*10^(log 204)]