Question

Se liga a = 2 e log b = -1. Calcule

A= log b a
B= log a b
C= log a b²

Answer 1

log a=2

log b=-1

A) log (b.a)=log b + log a substituindo log a= 2 e log b=-1

log (b.a)= -1+2 = 1

B) log (a.b)= log a + log b substituindo log a= 2 e log b=-1

log (a.b)= 2-1 = 1

C) log(a.b²)= log a + log b²

log(a.b²)= log a + 2log b substituindo log a= 2 e log b=-1

log(a.b²)=2+2(-1) = 2-2 = 0