Question

Se forem tirar duvidas usem o chat

Answer 1

Explicação passo-a-passo:

$\sf log_{4}~\sqrt{32}$

$\sf =log_{2^2}~\sqrt{2^5}$

$\sf =log_{2^2}~2^{\frac{5}{2}}$

Lembre-se que $\sf log_{b^m}~a^n=\dfrac{n}{m}\cdot log_{b}~a$

Logo:

$\sf log_{2^2}~2^{\frac{5}{2}}$

$\sf =\dfrac{\frac{5}{2}}{2}\cdot log_{2}~2$

$\sf =\dfrac{5}{2}\cdot\dfrac{1}{2}\cdot1$

$\sf =\dfrac{5}{4}$