Question

Se C= log²  2√2 e D= log 0,01 10, determine o valor de C+D

Answer 1

Se C= log²  2√2 e D= log 0,01 10, determine o valor de C+D

= log²  2√2 ==>2^x = 2.2^1/2 ==> 2^x = 2^(1+1/2) ==>2^x=2^(2+1)/2

2^x = 2^3/2 ==> x = 3/2


D= log 0,01 10 = x ==>(0,01)^x = 10^1 ==> (10^-2)^x = 10^1

 10^-2x = 10^1==> -2x = 1 ==> x = - 1/2

C+D =  3 - 1 ==> 2 ==> 1
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