se as matrizes a = (aij ) e b = (bij ) estao assim definidas :
aij = 1 se i = j
aij = 0 se ≠ j
bij = 1 se i + j = 4
bij = 0 se i + j ≠ 4
onde 1 ≤ i,j ≤ 3 então a matriz A + B é ?
Soluções para a tarefa
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Com as regras dadas montamos:
![\displaystyle A= \left \{ {{a_{ij}=1,~i=j} \atop {a_{ij}=0,~i \neq j} \right.= \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\\0&0&0\\\vdots&\vdots&\vdots\end{array}\right] \displaystyle A= \left \{ {{a_{ij}=1,~i=j} \atop {a_{ij}=0,~i \neq j} \right.= \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\\0&0&0\\\vdots&\vdots&\vdots\end{array}\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle+A%3D+%5Cleft+%5C%7B+%7B%7Ba_%7Bij%7D%3D1%2C%7Ei%3Dj%7D+%5Catop+%7Ba_%7Bij%7D%3D0%2C%7Ei+%5Cneq+j%7D+%5Cright.%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3B0%26amp%3B0%5C%5C0%26amp%3B1%26amp%3B0%5C%5C0%26amp%3B0%26amp%3B1%5C%5C0%26amp%3B0%26amp%3B0%5C%5C%5Cvdots%26amp%3B%5Cvdots%26amp%3B%5Cvdots%5Cend%7Barray%7D%5Cright%5D%C2%A0)
e
![\displaystyle B= \left \{ {{b_{ij}=1,~i+j=4} \atop {b_{ij}=0,~i+j\neq4}} \right. = \left[\begin{array}{ccc}0&0&1\\0&1&0\\1&0&0\\0&0&0\\\vdots&\vdots&\vdots\end{array}\right] \displaystyle B= \left \{ {{b_{ij}=1,~i+j=4} \atop {b_{ij}=0,~i+j\neq4}} \right. = \left[\begin{array}{ccc}0&0&1\\0&1&0\\1&0&0\\0&0&0\\\vdots&\vdots&\vdots\end{array}\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle+B%3D+%5Cleft+%5C%7B+%7B%7Bb_%7Bij%7D%3D1%2C%7Ei%2Bj%3D4%7D+%5Catop+%7Bb_%7Bij%7D%3D0%2C%7Ei%2Bj%5Cneq4%7D%7D+%5Cright.+%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26amp%3B0%26amp%3B1%5C%5C0%26amp%3B1%26amp%3B0%5C%5C1%26amp%3B0%26amp%3B0%5C%5C0%26amp%3B0%26amp%3B0%5C%5C%5Cvdots%26amp%3B%5Cvdots%26amp%3B%5Cvdots%5Cend%7Barray%7D%5Cright%5D+)
onde todos os elementos abaixo são iguais a zero.
a soma de A com B será:
![\displaystyle A+B= \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\\0&0&0\\\vdots&\vdots&\vdots\end{array}\right]+\left[\begin{array}{ccc}0&0&1\\0&1&0\\1&0&0\\0&0&0\\\vdots&\vdots&\vdots\end{array}\right]=\left[\begin{array}{ccc}0+1&0+0&0+1\\0+0&1+1&0+0\\1+0&0+0&0+1\\0+0&0+0&0+0\\\vdots&\vdots&\vdots\end{array}\right]\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\boxed{A+B=\left[\begin{array}{ccc}1&0&1\\0&2&0\\1&0&1\\0&0&0\\\vdots&\vdots&\vdots\end{array}\right]} \displaystyle A+B= \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\\0&0&0\\\vdots&\vdots&\vdots\end{array}\right]+\left[\begin{array}{ccc}0&0&1\\0&1&0\\1&0&0\\0&0&0\\\vdots&\vdots&\vdots\end{array}\right]=\left[\begin{array}{ccc}0+1&0+0&0+1\\0+0&1+1&0+0\\1+0&0+0&0+1\\0+0&0+0&0+0\\\vdots&\vdots&\vdots\end{array}\right]\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\boxed{A+B=\left[\begin{array}{ccc}1&0&1\\0&2&0\\1&0&1\\0&0&0\\\vdots&\vdots&\vdots\end{array}\right]}](https://tex.z-dn.net/?f=%5Cdisplaystyle+A%2BB%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3B0%26amp%3B0%5C%5C0%26amp%3B1%26amp%3B0%5C%5C0%26amp%3B0%26amp%3B1%5C%5C0%26amp%3B0%26amp%3B0%5C%5C%5Cvdots%26amp%3B%5Cvdots%26amp%3B%5Cvdots%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26amp%3B0%26amp%3B1%5C%5C0%26amp%3B1%26amp%3B0%5C%5C1%26amp%3B0%26amp%3B0%5C%5C0%26amp%3B0%26amp%3B0%5C%5C%5Cvdots%26amp%3B%5Cvdots%26amp%3B%5Cvdots%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%2B1%26amp%3B0%2B0%26amp%3B0%2B1%5C%5C0%2B0%26amp%3B1%2B1%26amp%3B0%2B0%5C%5C1%2B0%26amp%3B0%2B0%26amp%3B0%2B1%5C%5C0%2B0%26amp%3B0%2B0%26amp%3B0%2B0%5C%5C%5Cvdots%26amp%3B%5Cvdots%26amp%3B%5Cvdots%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%5Cboxed%7BA%2BB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3B0%26amp%3B1%5C%5C0%26amp%3B2%26amp%3B0%5C%5C1%26amp%3B0%26amp%3B1%5C%5C0%26amp%3B0%26amp%3B0%5C%5C%5Cvdots%26amp%3B%5Cvdots%26amp%3B%5Cvdots%5Cend%7Barray%7D%5Cright%5D%7D)
considerei que
(j [coluna] tende ao infinito, então teríamos infinitas colunas, por isso os pontinhos, já que j só precisa ser maior ou igual a 3.
e
onde todos os elementos abaixo são iguais a zero.
a soma de A com B será:
considerei que
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