Matemática, perguntado por amandaizuma842, 7 meses atrás

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Anexos:

Soluções para a tarefa

Respondido por ToquioItuno
3

\Large\boxed{\boxed{\boxed{{ Questa\~\o (1)}}}}}

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a) A + B

\left[\begin{array}{cc}0&3\\2& - 5\end{array}\right] + \left[\begin{array}{cc} - 2&4\\0& - 1\end{array}\right] \\  \\ \left[\begin{array}{cc}0 + ( - 2)&3 + 4\\2 + 0& - 5 + ( -1 )\end{array}\right] \\  \\ \left[\begin{array}{cc} - 2&7\\2& - 6\end{array}\right]

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b) A + C

\left[\begin{array}{cc}0&3\\2& - 5\end{array}\right] + \left[\begin{array}{cc} 4&2\\ - 6&0 \end{array}\right] \\  \\ \left[\begin{array}{cc}0 + 4&3 + 2\\2 + ( - 6)& - 5 +  0\end{array}\right] \\  \\ \left[\begin{array}{cc} 4&5\\ - 4& - 5\end{array}\right]

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c) A + B + C

\left[\begin{array}{cc}0&3\\2& - 5\end{array}\right] + \left[\begin{array}{cc} - 2&4\\0& - 1\end{array}\right]  + \left[\begin{array}{cc} 4&2\\ - 6&0 \end{array}\right]  \\  \\  \left[\begin{array}{cc} - 2&7\\2& - 6\end{array}\right] + \left[\begin{array}{cc} 4&2\\ - 6&0 \end{array}\right]  \\  \\ \left[\begin{array}{cc} - 2 + 4&7 + 2\\2 + ( - 6)& - 6 +  0\end{array}\right] \\  \\\left[\begin{array}{cc} 2&9\\ - 4& -6\end{array}\right]

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d) - A + B

 - \left[\begin{array}{cc}0&3\\2& - 5\end{array}\right] + \left[\begin{array}{cc} - 2&4\\0& - 1\end{array}\right] \\  \\ \left[\begin{array}{cc}0& - 3\\ - 2&  5\end{array}\right] + \left[\begin{array}{cc} - 2&4\\0& - 1\end{array}\right] \\  \\ \left[\begin{array}{cc}0 + ( - 2)& - 3 + 4\\ - 2 + 0&  5 + ( -1 )\end{array}\right] \\  \\ \left[\begin{array}{cc} - 2&1\\ - 2&4 \end{array}\right]

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\Large\boxed{\boxed{\boxed{{ Questa\~\o (2)}}}}}

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a) - A - B

- \left[\begin{array}{cc}2&1\\ - 3& 4\end{array}\right]  -  \left[\begin{array}{cc} 0& - 1\\2& 5\end{array}\right] \\  \\ \left[\begin{array}{cc} - 2& - 1\\ 3&  - 4\end{array}\right]  -  \left[\begin{array}{cc} 0& - 1\\2& 5\end{array}\right] \\  \\ \left[\begin{array}{cc} - 2  -  0& - 1  -  ( - 1)\\ 3  -  2&  - 4  -  5\end{array}\right] \\  \\ \left[\begin{array}{cc} - 2& 0\\ 1& - 9 \end{array}\right]

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b) A - Bt - C

\left[\begin{array}{cc}2&1\\ - 3& 4\end{array}\right]  -   { \left[\begin{array}{cc} 0& 2\\ - 1& 5\end{array}\right]}^{t}  -  \left[\begin{array}{cc} 3& 0\\ 6& 1\end{array}\right] \\  \\ \left[\begin{array}{cc}2&1\\ - 3& 4\end{array}\right]  -   { \left[\begin{array}{cc} 0& 2\\ - 1& 5\end{array}\right]}^{t}  \\  \\ \left[\begin{array}{cc} 2  -  0&  1  - 2\\  - 3  - ( - 1)&  4  -  5\end{array}\right] \\  \\ \left[\begin{array}{cc} 2&  - 1\\  - 2& - 1 \end{array}\right] \\  \\ \left[\begin{array}{cc} 2&  - 1\\  - 2& - 1 \end{array}\right] - \left[\begin{array}{cc} 3& 0\\ 6& 1\end{array}\right]  \\  \\ \left[\begin{array}{cc} 2  -  3&   - 1  - 0\\  - 2  - 6&   - 1  -  1\end{array}\right] \\  \\ \left[\begin{array}{cc}  - 1&  - 1\\  - 8& - 2 \end{array}\right]

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c) At + Ct

{\left[\begin{array}{cc}2& - 3\\1&4\end{array}\right] }^{t} +  {\left[\begin{array}{cc} 3&6\\0&1\end{array}\right]}^{t}  \\  \\ \left[\begin{array}{cc}2 + 3& - 3 + 6\\1 + 0&4 + 1\end{array}\right] \\  \\ \left[\begin{array}{cc} 5&3\\1& 5\end{array}\right]

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