Question

Se alguém souber fazer é para entregar até dia 31

Answer 1

$\Large\boxed{\boxed{\boxed{{ Questa\~\o (1)}}}}}$

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a) A + B

$\left[\begin{array}{cc}0&3\\2& - 5\end{array}\right] + \left[\begin{array}{cc} - 2&4\\0& - 1\end{array}\right] \\ \\ \left[\begin{array}{cc}0 + ( - 2)&3 + 4\\2 + 0& - 5 + ( -1 )\end{array}\right] \\ \\ \left[\begin{array}{cc} - 2&7\\2& - 6\end{array}\right]$

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b) A + C

$\left[\begin{array}{cc}0&3\\2& - 5\end{array}\right] + \left[\begin{array}{cc} 4&2\\ - 6&0 \end{array}\right] \\ \\ \left[\begin{array}{cc}0 + 4&3 + 2\\2 + ( - 6)& - 5 + 0\end{array}\right] \\ \\ \left[\begin{array}{cc} 4&5\\ - 4& - 5\end{array}\right]$

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c) A + B + C

$\left[\begin{array}{cc}0&3\\2& - 5\end{array}\right] + \left[\begin{array}{cc} - 2&4\\0& - 1\end{array}\right] + \left[\begin{array}{cc} 4&2\\ - 6&0 \end{array}\right] \\ \\ \left[\begin{array}{cc} - 2&7\\2& - 6\end{array}\right] + \left[\begin{array}{cc} 4&2\\ - 6&0 \end{array}\right] \\ \\ \left[\begin{array}{cc} - 2 + 4&7 + 2\\2 + ( - 6)& - 6 + 0\end{array}\right] \\ \\\left[\begin{array}{cc} 2&9\\ - 4& -6\end{array}\right]$

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d) - A + B

$- \left[\begin{array}{cc}0&3\\2& - 5\end{array}\right] + \left[\begin{array}{cc} - 2&4\\0& - 1\end{array}\right] \\ \\ \left[\begin{array}{cc}0& - 3\\ - 2& 5\end{array}\right] + \left[\begin{array}{cc} - 2&4\\0& - 1\end{array}\right] \\ \\ \left[\begin{array}{cc}0 + ( - 2)& - 3 + 4\\ - 2 + 0& 5 + ( -1 )\end{array}\right] \\ \\ \left[\begin{array}{cc} - 2&1\\ - 2&4 \end{array}\right]$

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$\Large\boxed{\boxed{\boxed{{ Questa\~\o (2)}}}}}$

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a) - A - B

$- \left[\begin{array}{cc}2&1\\ - 3& 4\end{array}\right] - \left[\begin{array}{cc} 0& - 1\\2& 5\end{array}\right] \\ \\ \left[\begin{array}{cc} - 2& - 1\\ 3& - 4\end{array}\right] - \left[\begin{array}{cc} 0& - 1\\2& 5\end{array}\right] \\ \\ \left[\begin{array}{cc} - 2 - 0& - 1 - ( - 1)\\ 3 - 2& - 4 - 5\end{array}\right] \\ \\ \left[\begin{array}{cc} - 2& 0\\ 1& - 9 \end{array}\right]$

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b) A - Bt - C

$\left[\begin{array}{cc}2&1\\ - 3& 4\end{array}\right] - { \left[\begin{array}{cc} 0& 2\\ - 1& 5\end{array}\right]}^{t} - \left[\begin{array}{cc} 3& 0\\ 6& 1\end{array}\right] \\ \\ \left[\begin{array}{cc}2&1\\ - 3& 4\end{array}\right] - { \left[\begin{array}{cc} 0& 2\\ - 1& 5\end{array}\right]}^{t} \\ \\ \left[\begin{array}{cc} 2 - 0& 1 - 2\\ - 3 - ( - 1)& 4 - 5\end{array}\right] \\ \\ \left[\begin{array}{cc} 2& - 1\\ - 2& - 1 \end{array}\right] \\ \\ \left[\begin{array}{cc} 2& - 1\\ - 2& - 1 \end{array}\right] - \left[\begin{array}{cc} 3& 0\\ 6& 1\end{array}\right] \\ \\ \left[\begin{array}{cc} 2 - 3& - 1 - 0\\ - 2 - 6& - 1 - 1\end{array}\right] \\ \\ \left[\begin{array}{cc} - 1& - 1\\ - 8& - 2 \end{array}\right]$

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c) At + Ct

${\left[\begin{array}{cc}2& - 3\\1&4\end{array}\right] }^{t} + {\left[\begin{array}{cc} 3&6\\0&1\end{array}\right]}^{t} \\ \\ \left[\begin{array}{cc}2 + 3& - 3 + 6\\1 + 0&4 + 1\end{array}\right] \\ \\ \left[\begin{array}{cc} 5&3\\1& 5\end{array}\right]$