Question

Se A = 8 elevado a potencia 1/3 + 16 elevado a potencia 1/4 - (-2)² + 8  elevado a potencia 4/3, qual o valor de A?

Answer 1

Olá, Francisca.

Temos que:

$\text{A}=8^{\frac{1}{3}}+16^{\frac{1}{4}}-(-2)^2+8^{\frac{4}{3}}$

Observe que:

$8^{\frac{1}{3}}=\sqrt[3]{8^1}=2\\\\16^{\frac{1}{4}}=\sqrt[4]{16}=2\\\\(-2)^2=(-2)\times(-2)=2^2=4\\\\8^{\frac{4}{3}}=\sqrt[3]{8^4}=\sqrt[3]{8^3\cdot8}=8\sqrt[3]{8}=8\times2=16$

Logo:

$\text{A}=2+2-4+16=16$