Question

Se A=2x²+5x-2 e B=-5x²+2x+1 e C=3x²-1x+4 determine:
A) A+B=
B)A-B=
C)B-C=
D)A-C=
E)C-A=

Answer 1

Resposta:

A) A+B=

$2 {x}^{2} + 5x - 2 + ( - 5 {x}^{2} + 2x + 1) \\ 2 {x}^{2} + 5x - 2 - 5 {x}^{2} + 2x + 1 \\ - 3 {x}^{2} + 7x - 1 \times ( - 1) \\ 3 {x}^{2} - 7x + 1$

B)A-B=

$2 {x}^{2} + 5x - 2 - ( - 5 {x}^{2} + 2x + 1) \\ 2 {x}^{2} + 5x - 2 + 5 {x}^{2} - 2x - 1 \\ 7 {x}^{2} + 3x - 3$

C)B-C=

$- 5 {x}^{2} + 2x + 1 - (3 {x}^{2} - x + 4) \\ - 5 {x}^{2} + 2x + 1 - 3 {x}^{2} + x - 4 \\ - 8 {x}^{2} + 3x - 3 \times ( - 1) \\ 8 {x}^{2} - 3x + 3$

D)A-C=

$2 {x}^{2} + 5x - 2 - (3 {x}^{2} - x + 4) \\ 2 {x}^{2} + 5x - 2 - 3 {x}^{2} + x - 4 \\ - {x}^{2} + 6x - 6 \times ( - 1) \\ {x}^{2} - 6x + 6$

E)C-A=

$3 {x}^{2} - x + 4 - (2 {x}^{2} + 5x - 2) \\ 3 {x}^{2} - x + 4 - 2 {x}^{2} - 5x + 2 \\ {x}^{2} - 6x + 6$