Question

Saudades que 10x = 20y e, log 2 = 0,3 calcule o valor de x/y

Answer 1

${10}^{x} = {20}^{y} \\ log( {10}^{x} ) = log( {20}^{y} ) \\ x log(10) = y log(20) \\ x \times 1 = y \times log(2 \times 10) \\ x = y( log(2) + log(10) ) \\ \frac{x}{y} = 0.3 + 1 \\ \boxed{\frac{x}{y} = 1.3}$