Question

sao duas questões ok?

1) x²+2x+2x+4

2) x²-2x-2x+4

espero q possam me ajudar nisso

Answer 1

1. x²+2x+2x+4

x² + 4x + 4 = 0

Onde:

a = 1 ; b = 4 ; c = 4

Lembrando que:

∆ = b²—4*a*c

∆ = 4²—4*1*4

∆ = 16 —16

∆ = 0

$\large\boxed{\boxed{{x_{1,2}=\frac{-b\pm\sqrt{\Delta}}{2*a}}}}}}$

x1 = (—4+0)/2*1

x1 = —4/2 = —2

x1 = —2

x2 = (—4—0)/2*1

x2 = —4/2 = —2

x2 = —2

Sol : { —2 }

B)

x² —2x — 2x + 4

x² —4x + 4 = 0

Onde:

a = 1 ; b = —4 ; c = 4

Lembrando que:

∆ = b² — 4*a*c

∆ = (—4)² — 4*1*4

∆ = 16 — 16

∆ = 0

x1 =( 4+0)/2*1

x1 = 4/2 = 2

x1 = 2

x2 = (4—0)/2*1

x2 = 4/2 = 2

x2 = 2

Sol: { 2 }

Dúvidas??Comente!!