Question

Sabendo - se que: logx^a=8 , logx^b=2 ,logx^c=1 , calcular

Answer 1

Resposta:

a) 40

b) 22/3

Explicação passo-a-passo:

a)

logx (a^5. c^2) / b =

logx a^5 + logx c^2 - logx b =

5.logx a + 2.logx c - logx b =

5.8 + 2.1 - 2 =

40 + 2 - 2

40

b)

logx raizcub(a^2. b^6)/(c^2) =

logx (a^2. b^6)^(1/3)/(c^2) =

logx (a^2. b^6)^(1/3) - logx c^2 =

(1/3).logx a^2. b^6 - 2.logx c =

(1/3).[2.logx a + 6.logx b] - 2.logx c =

(1/3).[2.8 + 6.2] - 2.1 =

(1/3).[16 + 12] - 2 =

(1/3). 28 - 2 =

(28 - 6)/3 =

22/3

Blz?

Abs :)