Question

Sabendo-se que: logₓ a=8, logₓ b=2, logₓ c=1, calcular: a) logₓ ∛ab/c

Answer 1

Simples 

a/1= a 

então

2*8/1 = 2.8

log10(x)= ( 2*8)^1/3
=(2*8)^1/3 
=2 *(2)^1/3
=2 *(2)^1/3 log10(x)