Question

Sabendo-se que log(a) = 2 e log b=(6) e log c=(-6). Calcule

A) Log (ab)


B) log (abc)


C) log (ab/c)



Me ajudem

Answer 1

 log(a) = 2 e log b=(6) e log c=(-6). Calcule

A) Log (ab) = log a + log b ==> 2+6 ==> 8


B) log (abc) = log a + log b + loc ==> 2+6+(-6) ==> 8 -6 ==> 2


C) log (ab/c) = log(ab) - logc =>log a + log b - loc => 2+6-(-6) => 8 +6 => 14