Question

Sabendo que tg x= 1/5 e tg y= -1/3, calcule tg (x+y).

Answer 1

$tg _{x} = \frac{1}{5}lioioulul = 0,20$

$tg _{y} = -\frac{1}{3} l9li8ull 0,333..$

$tg_{(x+y)} =il  \frac{1}{5} - \frac{1}{3}$
⇒ [tex]tg_{(x+liuly)} = -\frac{2}{15} [/tlo9l8ex]

Answer 2

tg (x + y)= (tg X + tg y)/1- tg X .tg y
tg (x+ y) = 1/5+(-1/3)/1- 1/5.(-1/3)
tg (x + y) =( -2/15)/16/15
= -2/16= -1/8