Question

sabendo que logb a = x e logb c = y o valor de(o resto está na imagem) ​

Answer 1

Resposta:

$log_{b} (\frac{a.c^{3} }{b^{2}} ) = log_{b} (a.c^{3}) - log_{b} (b^{2} ) = log_{b} (a) + log_{b} (c^{3} ) - log_{b} (b^{2} ) =\\\\ log_{b} (a) + 3.log_{b} (c ) - 2.log_{b} (b) = x +3.y -2 .1 = x +3y -2$

Acho que é isso. Curte ai e deixa estrelas.....

Answer 2

Explicação passo-a-passo:

$\sf log_{b}~\Big(\dfrac{a\cdot c^3}{b^2}\Big)=log_{b}~(a\cdot c^3)-log_{b}~b^2$

$\sf log_{b}~\Big(\dfrac{a\cdot c^3}{b^2}\Big)=log_{b}~a+log_{b}~c^3-log_{b}~b^2$

$\sf log_{b}~\Big(\dfrac{a\cdot c^3}{b^2}\Big)=log_{b}~a+3\cdot log_{b}~c-2\cdot log_{b}~b$

$\sf log_{b}~\Big(\dfrac{a\cdot c^3}{b^2}\Big)=x+3\cdot y-2\cdot1$

$\sf \red{log_{b}~\Big(\dfrac{a\cdot c^3}{b^2}\Big)=x+3y-2}$