Question

Sabendo que log2= 0,301, calcule o valor de:
a) log 200

Answer 1

$\log_{}2=0,301$

$\log_{}200=\log_{}2. 10^{2} =\log_{}2+\log_{} 10^{2} =0,301+2.\log_{}10=0,301+2.1$$=0,301+2=2,301$

Answer 2

Resposta:

log2=2,301

Explicação passo-a-passo:

log200 = log(100x2)=log100+log2

sendo log2=0,301

e log100=2,pois 10x10=100

log2+log100=

0,301+2= 2,301